Skip to article frontmatterSkip to article content

3. Power Amplifier

The power amplifier provides the amplification required to produce audible sound on the loudspeakers. It also serves as a filter, removing unwanted frequency components.

Frequency Dependent Amplification with an Op-amp

As you may recall from Linear Circuits, an op-amp circuit with a purely resistive coupling network has frequency-independent amplification. If at least one frequency-dependent impedance ZZ (such as a capacitor) is introduced, the amplification becomes frequency dependent. As a result, the gain is no longer the same for all frequencies.

In the following section, we examine simple first-order filter circuits. These are obtained by replacing one of the impedances ZZ in the coupling network with a resistor-capacitor combination. The remaining impedances ZiZ_i are resistors. Depending on the configuration, the circuit exhibits either high-pass or low-pass behavior.

Assignments

1. Inverting Amplifier with a First-order Low-pass Filter

ripple

Figure 1:An inverting amplifier with a first-order low-pass filter.

Assignments:

  1. Derive the transfer function H(f)=uousH(f) = \frac{u_o}{u_s}.

  2. Show that the transfer function has the form

    H(f)=α1+jff0H(f) = \frac{\alpha}{1 + j\frac{f}{f_0}}

    Express α\alpha and f0f_0 in terms of R1R_1, R2R_2, and C2C_2.

  3. Show that the power transfer equals G(f)=H(f)2=0.5α2G(f) = |H(f)|^2 = 0.5 \cdot \alpha^2 for f=f0f = f_0.

  4. Sketch G(f)G(f) as a function of frequency.

  5. Repeat the sketch using a logarithmic frequency scale. Plot log10f\log_{10}{f} on the x-axis and 10log10G(f)10 \cdot \log_{10}{G(f)} (in dB) on the y-axis.

  6. Show that 10log10G(f)10 \cdot \log_{10}{G(f)} at f=f0f = f_0 is equal to -3 dB relative to its value at f=0f = 0. This f0f_0 is therefore also called the -3 dB frequency, denoted f3dBf_{-3dB}.

  7. Show that for f>f0f > f_0, G(f)G(f) decreases by a factor of ~4 (6 dB) for each doubling of frequency. For this reason, f0f_0 is also called the cut-off frequency: below f0f_0 the transfer is flat, above f0f_0 the transfer decreases.

2. Inverting Amplifier with a First-order High-pass Filter

ripple

Figure 2:An inverting op-amp circuit with a first-order high-pass filter.

Assignments:

  1. Derive the transfer function H(f)=uousH(f) = \frac{u_o}{u_s}.

  2. Show that it has the form

    H(f)=jff0/α1+jff0H(f) = \frac{j\frac{f}{f_0 / \alpha}}{1 + j\frac{f}{f_0}}

    Express α\alpha and f0f_0 in terms of R1R_1, R2R_2, and C1C_1.

  3. Show that G(f)=H(f)2=0.5α2G(f) = |H(f)|^2 = 0.5 \cdot \alpha^2 for f=f0f = f_0.

  4. Sketch G(f)G(f) as a function of frequency.

  5. Repeat the sketch on a logarithmic frequency scale, plotting 10log10G(f)10 \cdot \log_{10}{G(f)}.

  6. Show that 10log10G(f)10 \cdot \log_{10}{G(f)} at f=f0f = f_0 is equal to -3 dB relative to the value for ff \to \infty. Thus, f0f_0 is also called the -3 dB frequency f3dBf_{-3dB}.

  7. Show that for f<f0f < f_0, G(f)G(f) decreases by a factor of ~4 (6 dB) for each halving of the frequency.

3. Non-inverting Amplifier with a First-order Low-pass Filter

ripple

Figure 3:A non-inverting op-amp circuit with a first-order low-pass filter. This circuit is often used to limit the amplifier input bandwidth, for example above 20 kHz.

Assignments:

  1. Derive H(f)=uousH(f) = \frac{u_o}{u_s}.

  2. Show that

    H(f)=α11+jff0H(f) = \alpha \cdot \frac{1}{1 + j\frac{f}{f_0}}

    Express α\alpha and f0f_0 in terms of R1R_1, R2R_2, R3R_3, and C4C_4.

  3. Show that G(f)=H(f)2=0.5α2G(f) = |H(f)|^2 = 0.5 \cdot \alpha^2 at f=f0f = f_0.

  4. Sketch G(f)G(f) vs. frequency.

  5. Repeat the sketch on a logarithmic frequency scale, plotting 10log10G(f)10 \cdot \log_{10}{G(f)}.

  6. Show that 10log10G(f)10 \cdot \log_{10}{G(f)} at f=f0f = f_0 is -3 dB relative to f=0f = 0.

  7. Show that for f>f0f > f_0, G(f)G(f) decreases by a factor of ~4 (6 dB) for each doubling of frequency.

4. Non-inverting Amplifier with a First-order High-pass Filter (1)

A non-inverting op-amp with a first-order high-pass filter.

Figure 4:A non-inverting op-amp with a first-order high-pass filter. Commonly used to block very low frequencies (f<20f < 20 Hz) and DC offsets, which could otherwise damage speakers.

Assignments:

  1. Derive the transfer function H(f)=uousH(f) = \frac{u_o}{u_s}.

  2. Show that the transfer function is of the following form:

    H(f)=α1+jff11+jff2H(f) = \alpha \cdot \frac{1+j\frac{f}{f_1}}{1+j\frac{f}{f_2}}

    and express α\alpha, f1f_1, and f2f_2 in terms of the component values R1R_1, R2R_2, R3R_3, R4R_4, and C1C_1.

  3. Show that f1<f2f_1 < f_2 and that the power transfer G(f2)=H(f2)2=0.5G(f)G(f_2) = |H(f_2)|^2 = 0.5 \cdot G(f \rightarrow \infty) if f1f2f_1 \ll f_2. This assumption holds for the following assignments.

  4. Show that for ff1f \ll f_1, G(f)=α2G(f) = \alpha^2. Furthermore, show that for ff2f \gg f_2 (this is for ff \rightarrow \infty), G(f)α2f22f12G(f) \rightarrow \alpha^2 \cdot \frac{f_2^2}{f_1^2}.

  5. Sketch the power transfer function G(f)G(f) as a function of the frequency.

  6. Repeat the sketch on a logarithmic frequency scale, plotting 10log10G(f)10 \cdot \log_{10}{G(f)}.

  7. Show that the value of 10log10G(f)10 \cdot \log_{10}{G(f)} for the frequency f=f2f = f_2 is -3 dB relative to the value for ff \rightarrow \infty. f2f_2 is therefore sometimes referred to as the -3dB frequency (f3dBf_{-3dB}).

  8. Show that for frequencies f<f2f < f_2, the value of G(f)G(f) decreases by a factor of ~4 (6 dB) for each halving of the frequency.


5. Non-inverting Amplifier with a First-order High-pass Filter (2)

Another non-inverting op-amp with a first-order high-pass filter.

Figure 5:Another non-inverting op-amp with a first-order high-pass filter. This version completely blocks DC and subsonic signals.

Assignments:

  1. Derive the transfer function H(f)=uousH(f) = \frac{u_o}{u_s}.

  2. Show that the transfer function is of the following form:

    H(f)=αjff01+jff0H(f) = \alpha \cdot \frac{j\frac{f}{f_0}}{1+j\frac{f}{f_0}}

    and express α\alpha and f0f_0 in terms of the component values R1R_1, R2R_2, R4R_4, and C3C_3.

  3. Show that the power transfer G(f)=H(f)2=0.5α2G(f) = |H(f)|^2 = 0.5 \cdot \alpha^2 for f=f0f = f_0.

  4. Sketch the power transfer function G(f)G(f) as a function of the frequency.

  5. Repeat the sketch on a logarithmic frequency scale, plotting 10log10G(f)10 \cdot \log_{10}{G(f)}.

  6. Show that the value of 10log10G(f)10 \cdot \log_{10}{G(f)} for the frequency f=f0f = f_0 is -3 dB relative to the value for ff \rightarrow \infty. f0f_0 is therefore sometimes referred to as the -3dB frequency (f3dBf_{-3dB}).

  7. Show that for frequencies f<f0f < f_0, the value of G(f)G(f) decreases by a factor of ~4 (6 dB) for each halving of the frequency.

Power Amplifier Circuit

Circuit diagram of the power amplifier that will be used for the audio system.

Figure 6:Circuit diagram of the power amplifier that will be used for the audio system.

The power amplifier used in this project is shown in Figure 6. It is based on the LM3886 op-amp. You are provided with a universal amplifier PCB that allows building the schematic shown in Figure 7 and Figure 8.

ripple

Figure 7:Universal amplifier circuit.

ripple

Figure 8:Supply circuit of the audio amplifier.

The circuit consists of:

The universal amplifier can be configured as inverting or non-inverting, with optional filters depending on which components (RaR_a, CaC_a, RbR_b, RcR_c, C1C_1^*, CXC_X) are placed or omitted. Connections are made via jumpers at P2P_2 and P3P_3.

The input connector is P1P_1, and the output connector is P4P_4.

The supply circuit includes diodes (D1D_1, D2D_2) for reverse polarity protection and capacitor combinations (C3C_3C8C_8) for filtering. Electrolytic capacitors are paired with ceramics to ensure effective high-frequency filtering.

Building the Circuit

The double-sided PCB is shown in Figure 9 and Figure 10:

Silk screen of the power amplifier PCB

Figure 9:Component side of the power amplifier PCB, showing the silk screen.

Silk screen including the traces.

Figure 10:Silk screen including the traces.

What is a silk screen?

A silk screen (also called silkscreen or solder mask overlay) is a printed layer on a PCB that shows component labels, reference designators (like R1, C1, IC1), component outlines, and other helpful text or symbols. It helps identify where components should be placed and provides important information for assembly and troubleshooting. The silk screen is typically white or yellow text/graphics printed on top of the solder mask.

Connector usage:

3-pin pin header and jumper cap

Figure 11:3-pin pin header and jumper cap

Socket header

Figure 12:Socket header

Component soldered to a pin header

Figure 13:Component soldered to a pin header


Assignment

Step 1: Design

Determine the function of each component in the amplifier circuit and select component values such that the amplifier meets the following requirements:

  1. The amplifier circuit has a non-inverting configuration.

  2. The voltage gain in the passband equals 25.

  3. The passband of the amplifier is 20 Hz-40 kHz (-3 dB bandwidth). This means that the signal components with frequencies 𝑓 < 20 Hz and 𝑓 > 40 kHz will be suppressed, relative to the signal components with frequencies of 20 Hz < 𝑓 < 40 kHz.

  4. The DC gain of the amplifier must be 1. This prevents and amplified version of the input offset voltage to be present at the output.

What is input offset voltage?

In a perfect op-amp, equal voltages at both inputs should produce zero output. However, manufacturing tolerances create component mismatches that result in a small DC offset voltage (typically a few millivolts) appearing between the inputs. This offset gets amplified by the circuit’s DC gain, potentially creating a significant DC error at the output.

In audio applications, this DC component can:

  • Damage speakers if the offset is large enough

  • Reduce the available dynamic range

  • Cause audible pops or clicks when the amplifier is turned on/off

That’s why requirement 4 specifies that the DC gain must be 1 - this prevents the amplification of any input offset voltage, keeping the DC output close to zero even if there’s a small offset present at the input.

Convert your theoretical component values into values that are available according to what components are available (see E-series). Make sure that you adjust in the right direction so that the requirements are still met (with a margin).

Step 2: Simulate

Step 3: Build

Why a heat sink?

A heat sink is essential for the LM3886 power amplifier because it dissipates heat generated during operation. Power amplifiers convert some of the input power into heat rather than useful output power - this is especially significant when driving loads or operating at high power levels.

Without adequate cooling, the chip temperature can rise to dangerous levels, causing:

  • Activation of built-in thermal protection (reducing output power)

  • Permanent damage to the op-amp

  • Unstable operation or complete failure

The heat sink provides a large surface area to transfer heat away from the chip to the surrounding air, keeping the operating temperature within safe limits and ensuring reliable performance.

What is thermal paste?

Thermal paste (also called thermal compound or thermal grease) is a thermally conductive material applied between a heat-generating component (like the LM3886 op-amp) and its heat sink. It fills microscopic air gaps and surface irregularities to improve heat transfer. However, if the op-amp and heat sink surfaces are flat and make good contact, thermal paste may not be necessary for this application. If you did not succeed in making a good connection, thermal paste can be solution.

See Figure 14 for a completed build.

Example PCB of a completed power amplifier.

Figure 14:Example PCB of a completed power amplifier.

Step 4: Inspect

Check your build for visual defects.

Use a magnifying glass or your phone camera with zoom if needed to inspect closely. Good lighting is essential for effective visual inspection.

  1. Solder joints:

    • All joints should be shiny and smooth (not dull or grainy)

    • No cold solder joints (insufficient solder or poor contact)

    • No solder bridges between adjacent pins or traces

    • No excessive solder that could create shorts

  2. Component placement:

    • All components are in their correct locations according to the schematic and PCB layout

    • Polarized components (electrolytic capacitors, diodes, op-amp) are oriented correctly

    • No components are missing

  3. Component integrity:

    • No damaged or cracked components

    • No bent or broken leads

    • Heat sink is properly mounted with no gaps

  4. PCB condition:

    • No damaged traces or pads

    • No solder splashes or debris on the board

  5. Connections:

    • All required connections are made

    • No loose wires or poorly secured connectors

    • Power supply connections are correct (check polarity)

If you find any issues, correct them before proceeding to testing.
See Problem Solving in Engineering.

Step 5: Test

Testing involves checking the actual circuits complies with the requirements through measurements, and determining the actual specifications of the circuit.

Before actual testing, you need to perform a controlled power up of the circuit. Such a step is to prevent the occurrence of cascading damage from high currents if there accidentally is a short circuit that has not be discovered during visual inspection.

Controlled Power Up

If you have reached this point, the next activity is actual checking if the requirements are met.

Checking Requirements
What is a data sheet? Where to find it?

A data sheet is a technical document provided by component manufacturers that contains detailed specifications, characteristics, and operating parameters for electronic components like integrated circuits, transistors, and other devices.

For the LM3886 op-amp used in this project, the data sheet includes:

  • Maximum offset input voltage specifications

  • Operating voltage ranges

  • Current consumption

  • Thermal characteristics

  • Pin configurations

  • Application circuits

  • Performance graphs

  • and much more

Where to find data sheets:

  • Manufacturer websites: Texas Instruments (TI) is the original manufacturer of the LM3886

  • Distributor websites: Digi-Key, Mouser, RS Components, etc.

  • Search engines: Simply search “LM3886 datasheet PDF”

  • Component databases: Sites like AllDataSheet.com or DataSheetCatalog.org

Always use official manufacturer data sheets when possible, as they contain the most accurate and up-to-date information for your design and testing requirements. The order given in the list of search locations above is typically a good search order.

If any or more of the requirements are not met, go into problem solving mode (Problem Solving in Engineering). If the gain at the low frequency crossover point (20 Hz) is inaccurate and/or the roll-off is not 6 dB/octave, suspect that the DC bias block (with Cx)C_x) is interfering with the high pass filter formed by C1C_1 and R2R_2.

If all is well: you are ready for final integration with the power supply and the filters.